The probability of a student passing any examination is

^{2}/_{3}. If the students takes three examination, what is the probability that he will not pass any of them-
**A.**^{2}/_{3} -
**B.**^{4}/_{9} -
**C.**^{8}/_{27} -
**D.**^{1}/_{27}

##### Correct Answer: Option D

##### Explanation

P(pass) = ^{2}/_{3}

P(not pass) = 1 – ^{2}/_{3} = ^{1}/_{3}

P(not passing any of the 3 Exams) = ^{1}/_{3} x ^{1}/_{3} x ^{1}/_{3}

= ^{1}/_{27}